Pearson Edexcel · GCSE · Physics
Course version: 1PH0 · Version from Sept 2016
Analyse velocity/time graphs to: a compare acceleration from gradients…
Full specification wording
Topic 2 – Motion and forces: 2.10 Analyse velocity/time graphs to: a compare acceleration from gradients qualitatively b calculate the acceleration from the gradient (for uniform acceleration only) c determine the distance travelled using the area between the graph line and the time axis (for uniform acceleration only)
A velocity/time graph plots velocity on the vertical axis against time on the horizontal axis.
Checked against the Pearson Edexcel 1PH0 specification (opens in a new tab) on .
- Point 10 of 32
Study notes
From the checked teaching notes for this specification point.
The idea
A velocity/time graph plots velocity on the vertical axis against time on the horizontal axis. The gradient of the line gives acceleration: a steeper line means greater acceleration, a horizontal line means zero acceleration (constant velocity), and a line sloping down means deceleration. To calculate acceleration for uniform acceleration, pick two points on a straight section and divide the change in velocity by the change in time, giving m/s². The area between the graph line and the time axis gives the distance travelled; for a straight-line section this area is a rectangle or triangle, so distance = area, in metres. For example, a triangle of base 4 s and height 10 m/s has area ½ × 4 × 10 = 20 m. Use gradient for acceleration and area for distance, and apply the calculation methods only where acceleration is uniform.
What earns the marks
- Compares gradients qualitatively, stating that a steeper gradient means greater acceleration.
- Calculates acceleration as the gradient, dividing change in velocity by change in time with unit m/s².
- Determines distance travelled from the area between the graph line and the time axis, in metres.
- Splits a compound area into rectangles and triangles and sums them to find total distance.
- Applies the gradient and area methods only to sections of uniform acceleration.
- Reads values from the axes accurately, including the time interval chosen for the gradient.
Common mistakes and how to put them right
Reads the height of the line as distance.
Put it right: Use the area under the line for distance and the gradient for acceleration.
Divides time by velocity when finding the gradient.
Put it right: Divide change in velocity by change in time.
Treats a curved section as uniform acceleration.
Put it right: Apply the calculation methods only to straight-line sections.
Omits units or mixes them.
Put it right: Give acceleration in m/s² and distance in m.
Exam tips
- Mark the two points you use for the gradient and show the change in velocity and change in time clearly.
- Shade the area you are calculating and label each rectangle or triangle before adding them.
- Check that a steeper line gives a larger acceleration value, as a quick sanity check.
Try the lesson
The start of the Topic 2 – Motion and forces: 2.10 Analyse velocity/time graphs to: a compare acceleration from gradients qualitatively b calculate the acceleration from the gradient (for uniform acceleration only) c determine the distance travelled using the area between the graph line and the time axis (for uniform acceleration only) lesson, made from checked teaching notes for this specification point.
Have a go first
On a velocity/time graph, a horizontal line at 6 m/s from 0 s to 4 s represents motion with which property?
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Test your understanding of Topic 2 – Motion and forces: 2.10 Analyse velocity/time graphs to: a compare acceleration from gradients qualitatively b calculate the acceleration from the gradient (for uniform acceleration only) c determine the distance travelled using the area between the graph line and the time axis (for uniform acceleration only)
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